Let side of first square be x and the side of another square be y.
difference in perimeter of two squares:-
and x=4+y---take this(1)
sum of areas of two squares:-
Put (1) here
2(y²+4y-192)=0 (here we have taken 2 common and take to another side. then it becomes:-)
we have done with factorisation method:-
either:- | or:-
y+16=0 | y-12=0
y= -16 | y=12
we will take y=12 because y being side cannot be negative.
put y=12 in (1)
and hence, Side of first square= x = 16
and Side of another square= y = 12.