The total outcomes=4 (H,H) (T,T) (T,H) (H,T)
favourable outcomes=3
So, probability=3/4
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Reality is that ...Probability is nothing we say if we are using 2 coins then it's probability will be 50-50 but we are wrong .....It depends on the height of throwing force of gravitation and many other points too AND one thing there is no 50-50 choice for any thing in this world .....It's all rubbish
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If a coin is tossed twice
S= { (H,H),(T,H),(H,T),(T,T) }
n(S) = 4

let A be the event that atleast one tail occurs
A ={ (T,H),(H,T),(T,T)}
n(A)= 3
therefore P(A)=3/4
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