# How many molecules are present in 34g of ammonia

2
by Loki8

2016-03-02T15:20:54+05:30

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No of molecules = ×avagadro number
molar mass of ammonia = atomic mass of nitrogen * 1+ atomic mass of hydrogen*3

14*1+1*3
14+3=17 g

34/17*6.022*=12.044*
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Mark as best plzz
2016-03-02T15:29:04+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
molar mass of ammonia = NH₃ = 14 + 1*3 = 14 + 3 = 17 u
1 mole = 17 g
therefore no. of moles in 34 g ,
= given mass / molar mass
= 34/17
= 2 moles

therefore ,

1 mole = 6.022*10²³

2 moles = 6.022*10²³ * 2 = 12.044 * 10²³
therefore 34 g of NH₃ contains 12.044*10²³ molecules .

i hope it helps.....