# Two opposite angles of a parallelogram are (3x - 2) and (63 - 2x).find all the angles of parallelogram

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by pritisweetty

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by pritisweetty

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i.e..(3x-2)=(63-2x)

3x-2=63-2x

3x+2x=63+2

5x=65

x=65/5

x=13

substituting x =13 we get

3×13-2=63-2×13

37 = 37

so the angles are 37° , 180°-37°,37° and 180°-37°

i.e. 37°,143°,37°and 143°

3x + 2x = 63 + 2

5x = 65

x = 65/5 = 13

3 * 13 - 2 = 37

63 - 2 * 13 = 37

Sum of 2 angles = 74

Total sum of angles in a parallelogram = 360

360-74 = 286

286/2 = 143

Therefore angles are 37, 143 , 37 & 143.