# Each edge of cube is increased by 50%.finds the percentage increase in surface areas.

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by adeshpartap

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by adeshpartap

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now the edge is increased by 50 %

so 50% of a = 50/100 ×a= a/2

now the new edge = a/2 + a = a/2+ 2a/2

=3a/2

now the surface area of the original cube = 6a²

and the surface area of the new cube = 6a² = 6 × (3a/2)²

= 27a²/2

now the increase in surface area = 27a²/2 - 6a²

= 27a²/2 - 12a²/2

= 15a²/2

now the percentage increase in surface area = 15a²/2/6a² × 100

= 15a² / 2× 6a² ×100

= 125 %

I hope I am correct !!

T.S.A of cube = 6a(a)

new edge = 3a/2

T.S.A of the original cube = 6(3a/2)(3a/2)

increase in T.S.A = 21(a)(a)

Increase % = 21(100)/6

= 350%