the velocity of bullet becomes halved while travelling through a distance of 6cm. Further distance it has to travel before coming to rest

along with procedure plz

by Himu

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the velocity of bullet becomes halved while travelling through a distance of 6cm. Further distance it has to travel before coming to rest

along with procedure plz

by Himu

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Initial velocity = u final velocity = v = u/2

distance = s = 6 cm

apply v² = u² + 2 a s => u²/4 = u² + 2 a 6 => -3/4 u² = 12 a

a = - 1/16 u² a is -ve and so it is slowing down

apply again v² = u² + 2a S

now v =0. initial speed = u²/4 So 0 = u²/4 - 2 1/16 u² S

S = 2 cm

distance = s = 6 cm

apply v² = u² + 2 a s => u²/4 = u² + 2 a 6 => -3/4 u² = 12 a

a = - 1/16 u² a is -ve and so it is slowing down

apply again v² = u² + 2a S

now v =0. initial speed = u²/4 So 0 = u²/4 - 2 1/16 u² S

S = 2 cm

Because velocity is inversely proportional to the distance travelled