# If the maximum velocity of a projectile is double the minimum velocity,the angle of projection is?

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Speed or magnitude of velocity at projection is u. Its components are Vx and Vy horizontally and vertically. Angle of projection with horizon is Ф.

Vx is constant = u cos Ф

Vy is highest at the time of projection and is zero at the top of parabolic path and again maximum when it reaches the ground.

*Velocity V = √(Vx² + Vy²) as Vx is constant , V is maximum when Vy is maximum at the point of projection and V is minimum when Vy is zero*

*Vmax = V itself Vmin = Vx = V cos Ф*

*Vmax/Vmin = 2 => Cos Ф = 1/2 => Ф = 60 degrees*

Vx is constant = u cos Ф

Vy is highest at the time of projection and is zero at the top of parabolic path and again maximum when it reaches the ground.

If the maximum projectile is doubled the minimum velocity, the angle of projectile is 60 degree