Answers

2016-03-06T07:57:38+05:30
From the above the diagrams CM and RN are the medians for the triangles.

we know that ΔABC≈ ΔPQR

AB/PQ = BC/QR = AC/PR ------------------------(1)
fromΔAMC and ΔPNR
∠A = ∠P
∠M = ∠N = 90
AC = PR
by ASA similarity 
ΔAMC ≈ΔPNR         ----PROVED
from this 
AC/PR = CM/RN = AM/PN
FROM ------(1)
AB/PQ = BC/QR = AC/PR
from that
CM/RN = AB/PQ     -----PROVED
from ΔBMC and ΔQNR
∠B = ∠Q
∠M = ∠N = 90
BC = RQ
by ASA similarity 
ΔBMC≈ΔQNR         ------PROVED
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