Answers

2016-03-04T20:45:12+05:30
As we have to prove triangle ABC as isosceles triangle we need to find the lengths of sides.
X=5,Y=-1,x=-3,y=2
AB²=(X-x)²+(Y-y)²
=(5+3)²+(-1-2)²
=64+9
=73
AB=√73

Now X=-3,Y=2,x=1,y=6
BC²=(X-x)²+(Y-y)²
=(-3-1)²+(2-6)²
=16+16
=32
BC=√32

As AB≠BC
We will find AC
X=5,Y=-1,x=1,y=6
AC²=(5-1)²+(-1-6)²
AC²=16+49
AC=√65
Its not a isosceles triangle.
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