Answers

2016-03-05T11:45:32+05:30
(a) In ΔADC and ABC
∠DAC=∠BAC(given)
∠DCA=∠BCA(given)
AC = AC(common)
∴ΔADC = ΔABC 

therefore by CPCT , AD= AB and BC = DC
⇒ABCD is a square 

(b)
In ΔBAD and BCD

BD = BD
AD = DC
BC = AB

by SSS rule ΔBAD =Δ BCD

∴∠CDB = ∠BDA
∠ABD=∠CBD

∴BD bisects ∠B and ∠C

PROVED.........

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