1. ABCD is a parallelogram. Points P and Q divides BC in three equal parts. Prove that
ar(APQ) = ar( DPQ) = 1/6 ar (ABCD).
2. traingles DAC and BAC are on same base AC. If vertex B and D are on opposite side of AC such that area of traingle BAC . Prove that OD=OB.
3. AB is a diametre of the circle whose centre is O. If angle ADC = 120 , calculate the angle BAC.
Please its urgent........