# In an experiment refractive index of glass was ovserved to be 1.45,1.56,1.54,1.44,1.54,1.53. then mean value of of tefractive index, mean value of absolute error,relative error,% error find? express the result in %error. .

1
by Sanup5577

2014-07-29T20:55:30+05:30

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Mean value of measurements = n = Sum of all measurements / 6 = 1.51
Absolute error of each measurement = | measurement - mean value |
=  0.06 , 0.05, 0.03, 0.07 , 0.03, 0.02     (only absolute value)
Mean value of Absolute error = Δn = 0.043    (arithmatic mean of above )
When you report refractive index from the experimnet , you say : 1.51 +- 0.043

Relative error = Δn / n = 0.043 / 1.51  =  0.0285
% relative error =  2.85 %