# 2 natural number differ by 4 and the sum of the square is 58 find the numbers

2
by RUTVI1

• Brainly User
2016-03-06T17:37:59+05:30

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7 and 3 .

The difference between two
= 7-3
= 4

7^2= 7*7 = 49
3^2= 3*3 = 9

Sum of their squares = 49+9
= 58

Therefore, the two numbers are 7 and 3
2016-03-06T17:41:45+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Let the numbers be x and y
x-y=4
therefore, x=y+4

x²+y²=58
(y+4)²+y²=58
y²+8y+16+y²=58
2y²+8y=42(58-16)
2(y²+4y-21)=0
y²+4y-21=0/2
y²+7y-3y-21=0
y(y+7)-3(y+7)=0
(y+7)(y-3)=0

therefore,y=-7,3
as the nos are natural, y=3
x=3+4=7

x=7
y=3
urs??
14
and urs
16....
i meant what is ur name??