Answers

2016-03-08T22:17:21+05:30
Given that 
log (x+y/3) = 1/2 (logx+logy)
log (x+y/3) = 1/2 (log xy)
log (x+y/3) = log √xy
remove the log on the both side 
(x+y/3) = √xy
(x+y/3)² = xy
x²+y²+2xy/9 = xy
x²+y²+2xy = 9xy
x²+y² = 9xy-2xy
x²+y² = 7xy   ------------------------(1)
form the another 
= x/y +y/x
= x²+y²/xy               from (1)
= 7xy / xy
= 7
0