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## Answers

In ∆ ABC,

AB = AC(Given)

AD = AD (Common)

Therefore, ∆ADB ~ ∆ADC

(By SAS)

AB = AC(Given)

AD = AD (Common)

Therefore, ∆ADB ~ ∆ADC

(By SAS)

AB=AC[given]

angle DAB= angle DAC [bcoz AD bisects angle A]

AD=AD [common]

So,by SAS

triangle ADB ~ triangle ADC

Hence showed

see picture for more explanation