Answers

2016-03-09T17:53:47+05:30
In ∆ ABC,
AB = AC(Given)
AD = AD (Common)
Therefore, ∆ADB ~ ∆ADC
(By SAS)
0
2016-03-09T18:43:02+05:30
In triangle ADB and triangle ADC
     AB=AC[given]
  angle DAB= angle DAC [bcoz AD bisects angle A]
  AD=AD [common]
So,by SAS
  triangle ADB ~ triangle ADC
    Hence showed
see picture for more explanation

0