# Express each of following as product of powers of thier prime factors?1]948

2
by srivathsun2002

2014-07-31T18:47:02+05:30

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948 = 2 × 2 × 3 × 79
Expressing as power,
948 = 2² × 3¹ × 79¹
pls answer to my another question
2014-07-31T19:04:01+05:30

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Since 948 is even number,  units digit is 8 - divisible by 8 - it has a factor 2. The last two digits 48 - it is divisible by 4 => number is divisible by 4.  Sum of all digits is 21 So it is divisible by 3.

948 = 2 * 2 * 3 * 79
Now 79 seems to be prime... so stop.
2² * 3 * 79