Answers

2016-03-13T20:23:25+05:30
Given that
the equation is x² - ax +b = 0
comparing with the ax² + bx +c = 0
a = 1 ; b = -a ;  c = b
then according to the problem  you told that sum and the product are equal
so, 
sum of zeroes =  -b/a
product of the zeroes = c/a 

-b/a = c/a 
a/1 = b/1
a = b
then the value of (a-b) = 0.
where a =b 
then
 = (a-b)
= a-a
= 0
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