Answers

2014-03-01T00:09:34+05:30
Let 7x + 9y = 35 ...........eq(i)
and 9x + 7y = 35 ..........eq(ii)
Multiplying eq(i) with 9 and eq(ii) with 7, we get
63x + 81y = 315 ............let it be eq(iii)
63x + 49y = 245 ............let it be eq(iv)
Subtracting eq(iv) from eq(iii), we get
32y = 70
or, y = 70/32
or, y = 
putting the value of y in eq(i), we get
7x + 9 X (70/32)  = 35
7x + 630/32 = 35
7x = 35 - 630/32
7x = (1120-630)/32
x = 490/(32X7)
x = 70/32
x = 
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