Am is perpendicular to bc.. N bc n od r parallel... So angle aod is 90°... Thn aod is at centre and abm is at circumference... So abm is 45°... Then using angle sum prop in triangle abm we get x = 45°
1 5 1
Then od is parallel to bc.. So angle cod is also 50°..
Cod is at centre but cbd at circumference.. So y is 25°
Pls mark as brainiest......
Y will get all the answer in study material or study ranker and CBSE info bank