In case of compound A , as it is reactive to alcoholic Cl , the Cl group must not be present at the terminal.
As there are only three carbons, the compound will be 2-chloropropane(
In case of compound B, on seeing the formula we can say it is an alkene.
Therefore the compound B will be Propene (
According to Markonikov Rule compound C will be 2-bromopropane (