In the given fig. PQR is the tangent to a circle at Q whose centre is O.AB is a chord parallel to PR and Angle BOR =60*.find angle AQB

:l I think it should be BQR that's why
Like this one
no divya in question paper its given as BOR
I think if u have took it from learncbse m.the question maybe wrong m.I don't know sorry bye!
its ok....btw i took it from EAD....


Angle AQB = half of angle BOR
sub the values and get the answer by intercepted angle theorem
why AQB is half BOR....can u state the reason please
construction of BOR
refer chap circle of std X of CBSE Board
Ull get it