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2016-03-16T21:09:00+05:30

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Let The Number be x and x + 2 ----[ Since The Numbers Are Even 
                                                             Numbers]

According To The Question,

x² + (x + 2)² = 164
x² + x² + 4x + 4 = 164
2x²  + 4x = 164 - 4
2x² + 4x -160 = 0

Dividing Whole Equation by 2
x² + 2x - 80 = 0
x² + 10x - 8x - 80 = 0
x(x + 10) -8(x + 10) = 0
(x - 8)(x + 10) = 0
x = 8 and not - 10 because x is a natural number
 
Therefore,

Answer = The Numbers Are 8and x + 2 = 8 + 2 = 10 

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2016-03-16T21:24:31+05:30

This Is a Certified Answer

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Let the first no. be x so the second would be x+2(as they are both even no.s)
 x^{2} +  (x+2)^{2} =164
 x^{2} + x^{2} + 4+4x=164
2 x^{2} +4x+4=164
 x^{2} +2x+2=82
 x^{2} +2x-80=0
D= b^{2} -4ac
  = 2^{2} -4(1)(-80)
   =4+320
      =324
x=-b+/- \sqrt{D} /2a

x=-b+ \sqrt{D} /2a
 =-2+√324/2(1)
  =-2+18/2=16/2=8

x=-b- \sqrt{D} /2a
 =-2-√324/2=-20/2=-10
But since it is given that hey are natural numbers -10 cannot be possible as it is a negative term

there fore x=8 and net no. is x+2=8+2=10

Therefore the numbers are 8 and 10

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Bhai thoda simple tarike se solve karke batao
It s so simple man....I just expanded it so that you can understand
If u want you can cut short some steps....which are obvious....like not needed to explain
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