# A cuboidal shaped slab of iron whose dimensions are 55cm×40cm ×15cm is melted and recast into a pipe. the outer radius and thickness of the pipe are 4cm and 1cm respectively. find the length of the pipe

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by khushi42

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by khushi42

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The inner radius of the pipe=4-1=3cm

55*40*15=πh(4²-3²)

h=(55*40*15*7)/22*7=5*20*15=1500cm=15m

Therefore the length of the pipe is 15m

The Brainliest Answer!

pie (Rsq_rsq)h=55×40×15

(22÷7)(4sq_3sq)h

=55×40×15

(22÷7)(16_9)h=55×40×15

(22÷7)7h=55×40×15

22×h=55×40×15

h=1500cm

h=15m