# Find the roots of the quadratic equation 12 abx2 – (9a2 – 8b2) x – 6ab = 0 in the variable x.

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by munnati22

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by munnati22

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12abx2- 9a2x+ 8b2x -6ab

3ax (4bx -3a)+2b (4bx-3a)

(3ax+ 2b) (4bx-3a)=0

ie x = -2b/3a , 3a/4b

3ax (4bx -3a)+2b (4bx-3a)

(3ax+ 2b) (4bx-3a)=0

ie x = -2b/3a , 3a/4b

12abx² - 9a²x - 8b²x - 6ab = 0

12abx² - 8b²x - 9a²x - 6ab = 0

4bx(3ax - 2b) -3a(3ax - 2b) = 0

(4bx - 3a) (3ax - 2b) = 0

4bx -3a =0

4bx = 3a

x = 3a/4b ----------1

3ax -2b =0

3ax = 2b

x = 2b/3a-----------2

∴the value of x is 3a/4b or 2b/3a

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