Find the area of the shaded region in figure 4, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as centre and a sector of circle of radius 6 cm with centre B is made.

Figure- It has a circle (fully shaded) and with the sector there is a triangle which is shaded except for a sector at the corner with B as centre.

Is the answer (627/7 + 9 root 3) sq. cm. ??

does it is correct
wait its wrong
wait ill ask this question again
no i got it only 3 min
I joined today and i just wasted 67 points on this question accidentally



 Area of sector outside triangle

=(angle O-angle AOB/360°)* \pi *6^{2}

=(300°/360°)* \pi *6^{2}

on solving we get

=94.28 sq cm

Area of triangle

= \sqrt{3}/4* side^{2}

on solving

=62.35 sq cm

Area of shaded region 

= 94.28 + 62.352 

= 156.632 sq cm

plz just mark as brainiest answer plz

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yes or no
yes i think
its half correct
till now
afterward i will do correction
The Brainliest Answer!
In the attachment provided i have solved the answer

At least this is correct ?

Thank You......!!!!!!!!!
Mark as brainliest if helpful...
Yours, Jahnavi. 
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plz plz plz mark mine as the brainliest
yes its totally correct!!
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