Answers

2016-03-18T21:02:57+05:30
Let the no. be x, x+2 ATQ (x)^2+(x+2)^2=202 2x^2+4x+4-202=0 2x^2+4x-198=0 Divide by 2 & then split it
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2016-03-18T21:19:38+05:30
Let the no be x and x+2

x² +(x+2)² =202
x² + x² + 4x +4 =202
2x²+4x-198 =0
2(x²+2x-99)=0
x²+11x-9x-99=0
x(x+11)-9(x+99)=0
(x+99)(x-9) =0
x=-99 0r 9


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