Answers

2016-03-19T11:10:25+05:30
Fare for the first kilometer =  10
susequent distance = 8 

x = 10+8(y-1)
x=10+8y-8
x=2+8y
0
2016-03-20T18:06:08+05:30
Let the total fare be Rs x km
Let the total distance be x km.
Now, ATQ
fare for the total distance is Rs 10
Subsequent distance is Rs 8
So, y=10+8×(x-1)
y= 10+8x-8
y=8x-2
0