What is the rationalising factor for 1/under root 7 - under root 3and hoe to simplify it further?

2
Comment has been deleted
Comment has been deleted
no actually the question is a bit different there is only one '1' in the numerator and under root 7 and under root 3 in the denominator
1/√7-√3 do you mean this?
yes

Answers

2014-08-03T13:38:32+05:30
1/√7-√3=(1-√21)/√7=(1-√21)/√7×(√7/√7)=(1-√21)×√7/(√7×√7)=(√7-7√3)÷7
0
2014-08-03T13:42:10+05:30
Rationalizing Factor is 

1/√7+√3. 

You need to multiply the number by this and you will rationalize the number. We can have infinite rationalizing factors. There are other factors also.
0