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## Answers

The Brainliest Answer!

by middle split method

⇒ + 2x + 3x + 6

now take commen out

⇒x(x+2)+3(x+2)

⇒(x+3)(x+2)

now for zeroes put 1 by one equalto zero

<1> x+3=0

x=-3

<2>x+2=0

x=-2

by splitting the middle term we get

x2+2x+3x+6=0

taking x as common and 3 common

x(x+2)+3(x+2)=0

x+2=0 x+3=0

x=-2 x=-3