Answers

  • Brainly User
2016-03-21T00:26:50+05:30
Let R and r be the radii of the circular ends of the frustum. (R> r) 

2R = 207.24 

R = 207.24/ (2 X 3.14)
 
R = 33 cm

2r = 169.56 cm 

r = 169.56 / (2 X 3.14) 

r = 27 cm

1² = h² + (R-r)² 

= 8² + (33-27)² 

l = 10 cm  


Whole surface area of the frustum
 
=  (R2 + r2 + (R+r)l)
 
= 3.14

((33)2 + (27)2 + (33+27)10)

= 3.14 (1089 +729 + 600)
 
= 3.14 X 2418 cm² 
 
= 7592.52 cm²

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