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Let the age of neetu is x years

age of mona = x - 20% of x = x - 0.2x = 0.8 x years

difference in age is (x -0.8x) = 0.2 years

age of mona = x - 20% of x = x - 0.2x = 0.8 x years

difference in age is (x -0.8x) = 0.2 years

**neetu is older than mona = [(difference in age)/(age of mona)]×100****= (0.2/0.8)×100 = 25%**