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2014-08-03T17:26:20+05:30

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Let the consecutive numbers be  a , a+1 , a+2
Their sum = a+ a+1+a+2  = 3a + 3 
so  3a+3 = 216  => 3a = 213  =>  a = 71
numbers are 71, 72, 73

1 3 1
2014-08-03T17:39:59+05:30
Let the first no be a..
so the rest of the nos are.a+1 and a+2.
  a+a+1+a+2=216
 or 3a+3=216
or 3a=213
  a=71.
so the nos are 71,72,73
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