Answers

2016-03-21T23:52:24+05:30
GIVEN,

3X+4Y+12Z=52
dividing both sides by √a2+b2+c2 we get,NOTE: a2 is a square,b2 is b sqare,c2 is c sqare

3/√9+16+144(X)+4/√9+16+144(Y)+12√9+16+144(z)=52/√9+16+144

=>3/13(x)+4/13(y)+12/13(z)=52/13=4
It is in the form form of lX + mY+nZ=P

where l,m,n are DC'S

therefore DC'S are (3/13,4/13,12/13)

Hope it helped u mate☺
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