#
Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:

2
## Answers

Let the time spent in covering 50 be t sec.

let the speed for the first trip be s=50/t

⇒t=50/s ........................... 1.

The speed for the 300 mile trip = 3×s = 3s

Let the time be t1

so ,

3s = 300/t1

t1=300/3s = 100/s ....................... 2.

Now,

Comparing the both time we will get,

**t1/t = (100/s) / ( 50/s)**

**t1/t = 100 ×s / 50 ×s**

**t1 / t = 100/50**

**t1 / t = 2/1 ..................... 3**

**⇒**

__2×t = t1 Ans.__

**So the correct option is (b).**

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**Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.**

We know that

**Speed = Distance/Time.**

So,

**Time = Distance/Speed.**

So,

**Time Taken to Cover a Distance of 50 miles on his First Trip = 50/x hr.**

**And Time Taken to Covered a Distance of 300 miles on his later trip = 300/3x hr.**

**= 100/x hr.**

**So,**

**Time Taken Later is Twice As before Time Taken**

**So,**

**ANSWER = (b) = Twice as Much**

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