# Mr. Jones sold two pipes at \$1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he: (a) broke even, (b) lost 4 cents, (c) gained 4 cents, (d) lost 10 cents, (e) gained 10 cents

2
by Deleted account

2016-03-22T10:55:58+05:30
Let The Cost Price for the first pipe be "x" Dollars

Selling Price = x + 20% of x
1.20 = x + 20x / 100
1.20 = x + x/5
1.20 = (5x + x)/5
1.20 * 5 = 6x
6 = 6x
x = 1 Dollar

So ,
Cost Price of The Pipe in Which Mr. Jones Got Profit of 20% = 1 Dollar

Let The Cost Price Of The Second Pipe be "y" dollar

Selling Price of second Pipe = y - 20% of y
1.20 = y - 20y/100
1.20 = y - y/5
1.20 = (5y - y)/5
1.20 * 5 =4y
6 = 4y
y = 6/4
y = 3/2
y = 1.5 Dollars

Total Cost Price Which Mr Jones Paid = 1 + 1.5
= 2.5 Dollars

Total Selling Price Which Mr Jones Received = 1.2 + 1.2
= 2.4 Dollar

Mr. Jones Lost 10 cents
so,

ANSWER = (d) = lost 10 cents

Hope U Understood
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2016-03-22T11:00:51+05:30

Solution =

20 % profit on \$ 1.20

= \$ 20/100 × 1.20

= \$ 0.20 × 1.20

= \$ 0.24

Similarly, 20 % loss on \$ 1.20

= \$ 20/100 × 1.20

= \$ 0.20 × 1.20

= \$ 0.24

Therefore, in one pipe his profit is \$ 0.24 and in the other pipe his loss is \$ 0.24.

Since both profit and loss amount is same so, it’s broke even.

Bro I Guess Your Answer is Wrong As profit is Always On Cost Price And Not Selling Price
And u Have Calculated Profit On Selling Price
Ohh Sorry
Its ok Atleast u Realized ur Mistake