# A mettalic box is in the shape of solid cuboid having dimensions 200*50*100cm it is recasting into a solid cube find the difference of surface areas of two solids

2
Log in to add a comment

Log in to add a comment

now, volume of the solid cube = volume of the solid cuboid

⇒(side)³= 1000000 cm³

⇒side = ∛1000000 = 100 cm

surface area of cuboid= 2(200×50)+2(50×100) +2(200×100)

=20000 +10000+40000

= 70000 cm³

surface area of cube = 6(100)² = 60000 cm²

200*50*100 = (side)^3

1000000 = (side)^3

cube of side on other side becomes cube root....

so..

100 cm= side

sur. ar.of cuboid

= 2 (lb+bh+hl)

=2(200*50+50*100+100*200)

2(10000+5000+20000)...

2(35000)= 70000cm2

sur. ar of cube= 6 (a×a)

=6(100*100)

= 6 (10000)

= 60000cm2

difference of their surface areas= area of cuboid - area of cube.

=70000-60000 cm2

= 10000 cm2.