# Let 'r' be the radius of a circle, h be the perpendicular distance from the centre of the circle to the chord then express length of chord in terms of r and h

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by namanineeraj

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by namanineeraj

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OB=r(radius) and OM=h(given)

as we know perpendicular drawn from centre to chord bisects the chord

∴in ΔOMB [by pyth theorem]

OB²=OM²+BM²

r²=h²+BM²

r²-h²=BM²

√(r²-h²)=BM

AB=2BM{perpendicular drawn from centre bisect the chord}

AB=2√(r²-h²)

length of chord will be 2√(r²-h²)

as we know perpendicular drawn from centre to chord bisects the chord

∴in ΔOMB [by pyth theorem]

OB²=OM²+BM²

r²=h²+BM²

r²-h²=BM²

√(r²-h²)=BM

AB=2BM{perpendicular drawn from centre bisect the chord}

AB=2√(r²-h²)

length of chord will be 2√(r²-h²)