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2016-03-24T21:18:37+05:30

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OB=r(radius) and OM=h(given)
as we know perpendicular drawn from centre to chord bisects the chord
∴in ΔOMB [by pyth theorem]
OB²=OM²+BM²
r²=h²+BM²
r²-h²=BM²
√(r²-h²)=BM
AB=2BM{perpendicular drawn from centre bisect the chord}
AB=2√(r²-h²)
length of chord will be 2√(r²-h²)
0
hope it is helpful............
thanks
my pleasure
which class are you from
10th