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The person needs a concave lens. eye is not able to focus the rays on to retina. they are gettng converged in front of retina. so diverging lens needed - so the rays converge on retina.

1/v - 1/u = 1/f          u very high - infinity  =>  1/v = 1/f     
v = f    P = 1/f
Image should be formed at close distance to eye. so f is small and power is very very high.    The lens could be a (very thin at center & very thick at the ends ) concave lens with very little radius of curvature.
The type of lens required by the person is a concave lens...HOPE IT HELPS...