Answers

2016-03-25T09:03:55+05:30
Two Digit palindromes should contain both digits same.

So,total no of two digits palindromes = 9 (11,22,33,...99)
To find 3 digit palindromes we will go with Permutations.

To become a 3 digit number palindrome 1st and 3rd digit should be same..(1_1,2_2,3_3.....9_9)

So this place can be filled in 9 way (number must not start with 0)

Second place can be filled with 10 ways (_0_,_1_,_2_,...._9_)

So total no of three digit palindromes =9×10=90

Now,1001 is the only one four digit palindrome between 10 and 1010

So, Total = 9 + 90 + 1 = 100
1 5 1
ok these rfrom various exams
-_- i asked which grade ? class ? std ?
i have a group of frndz on whatsapp. they upload various question they get troubled from
Ohk ohk
:-)