Answers

  • qais
  • Content Quality
2016-03-25T18:21:43+05:30
Let the numbers be a,b,c,d and e
(a+b+c+d+e)/5 =51
(a+b+c+d+e)= 255____(1)
(a+b+c)/3 = 42
⇒(a+b+c) = 126_____(2)
and (c+d+e)/3 =59
⇒(c+d+e) = 177____(3)
adding, (2) and (3) and subtracting with (1),
(a+b+2c+d+e) -(a+b+c+d+e) =303 - 255 = 48
⇒third number, c= 48

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2016-03-25T18:34:48+05:30
Let the no be a,b,c,d,e.
Acc. to question
(a+b+c+d+e)/5=51
a+b+c+d+e=255-------1
Now acc to ques
(a+b+c)/3=42
a+b+c=126
a+b=126-c---------2
(c+d+e)/3=59
d+e=177-c---------3
On putting the value of 2 and 3 in 1 we get,
126-c+c+177-c=255
c=48
therefore third no is 48
d+e=
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