Answers

  • qais
  • Content Quality
2016-03-25T18:35:52+05:30
1-2a -2b -3(a+b)²
= 1-2(a+b)-3(a+b)²
=1- 3(a+b) +(a+b) -3(a+b)²
=1[1-3(a+b)]+(a+b)[1-3(a+b)]
=[1-3(a+b)][1+(a+b)]
=(1-3a-3b)(1+a+b)
0
2016-03-25T18:36:15+05:30
1-2a-2b-3(a+b)²
=1-2(a+b)-3(a+b)²
let y=a+b
=1-2y-3y²
1-3y +y-3y ²
=(1-3y) y(1-3y)
=(1-3y)(1+y)
=(1-3a-3b) (1+a+b) 

0
plz mark brainlest
dont equate it with zero, it's expression not equation