Answers

2016-03-26T20:26:45+05:30
Let equation be - ax2+bx+c=0 Now divide eq. by a, we get, x2+(b/a)x=-(c/a) Now add [1/2*coefficient of x]2 both the sides making it - x2+2*(b/2a)x+(b/2a)2=(b/2a)2-(c/a) Now by id. (A+B)2,we get, [x+(b/2a)]2=[b2-4ac]/4a2
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