# The radius of sperical balloon increases from 6cm to 12cm as air is being pumped find the ratios of the surface areas of the balloon in both cases

1
by hetvipatel1

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by hetvipatel1

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S¹ = 4πr1²

S¹ = 4×π×36 = 144π --(1)

r2 = 12cm

S² = 4πr2²

S² = 4×π×144 = 576π ---(2)

Dividing both

S¹/S² = 144π/576π = 1/4

Hence ratio is 1:4

Note :- S¹ & S² Denotes surface area in both cases