P V0 = n R T n0 = number of moles of Oxygen, V0 = initial volume.

P & T are constant. V0 = k n0 where k is a constant

x O2 -> y Ozone

Let x moles of Oxygen be converted into y moles of O3

Volume V1 = k (n0 - x) + y k = k [ n0 - x + y ]

Change in volume = - 4 ml = - 0.004 = V1 - V0 = k [n0 - x + y] - k n0

__so k ( x - y) = 0.004 --- equation 1__

When turpentine is added, Ozone is completed dissolved in turpentine. Only remaining Oxygen O2 is present as gas.

Volume V2 = k (n0 - x)

change in volume = V2 - V1 = - 0.008 = k(n0 - x) - k (n0 - x + y)

__So k y = 0.008 __ equation 2

From equation 1 and 2 , k x = 0.012

so** k y / k x = y / x = 0.008 / 0.12 = 2/3**

__so 3 O2 ===> 2 molecules => 2 O3__