Answers

2016-03-27T13:31:09+05:30
Common multiples of 2 and 3 are 102,108,114,120 .............198
last term is 198
using te formula 
last term = first term +(number of terms -1) common difference
198=102+(n-1)6
(n-1)=96/6
n-1=16
n=17
by  using the formual
sum of n terms = no. of terms/2 (2first terms + (number of terms -1) d)
u can find the overall sum
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2016-03-27T13:33:21+05:30
Common multiples of 2 and 3 are 102,108,114,120 .............198
last term is 198
using te formula 
last term = first term +(number of terms -1) common difference
198=102+(n-1)6
(n-1)=96/6
n-1=16
n=17
by  using the formual
sum of n terms = no. of terms/2 (2first terms + (number of terms -1) d)

So if u do this u will get the answer as 2550
0