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## Answers

Half the diagonals, 3cm and 4cm

The diagonals divide the rhombus in four right angled triangles.

(Since, the diagonals of rhombus intersect at right angles)

So, using Pythagoras theorem,

a²+b² = c²

3²+4² = c²

25 = c²

c = √25

c = 5 cm

So, one side of the rhombus is 5cm.

Let AC = 6 and BD = 8

property Diagonals of rhombus bisect each other in right angle.

consider AC and BD meet at O

THen in triangle AOD

AD² = AO² + OD²

= (AC/2)² + (BD/2)²

= 3² + 4²

= 25

AD = √25

AD = 5 side of rhombus