Answers

2016-03-27T15:48:45+05:30
In triangle HIJ, the perimeter i.e., HI + IJ + HJ = 14.2 cm.
                        IJ = 5.2 cm
                        HI + HJ = 14.2 -5.2
                                     = 9 cm
                        angle I = 60degree
steps of 
construction:
1. d
raw a linesegment IJ = 5.2 cm
2. with I as centre construct angle I = 60 degrees
3. measure 
HI + HJ = 9 cm and cut an arc with I as centre and using a compass.
4. let that point of intersection be A.
5. join AJ.
6. draw the perpendicular bisector of AJ.
7. extend the bisector until it intersects AI at a point.
8. the point of intersection is H
9. join HJ. 
10. HIJ is the requied triangle 

1 4 1