# The length of a diagonal of a cubiod is 5root5 and the sum of its length ,breadth and heigth is 19 cm .find its surface area

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by ysnavneeth16

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by ysnavneeth16

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the sum of length ,breadth and heigth of the cuboid = 19cm = l+b+h

surface area of a cuboid = 2(lb+bh+lh)

(l+b+h)² = l² + b² + h² + 2lb+2bh+2lh

19² = (5√5)² + 2(lb+bh+lh)

361 = 125 + 2(lb+bh+lh)

2(lb+bh+lh) = 236cm

therefore surface area of the cuboid is 236cm