# Find out ( A + B + C + D ) such that AB x CD = DDD, where AB & CB are two digit numbers & DDD is three digits number.

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X C D

______

DDD

the value of D could be anything from 1 to 9

if D=1 DDD=111

D=2 DDD=222 and so on.

if we would take A=3, B=7, C=1, D=5

then DDD=555

so A+B+C+D= 3+7+1+5=16