In the figure, AB and AC are two cords of a circle of centre O and radius r. If AB=2AC and the perpendiculars drawn from the centre on these chords are of lengths 'a' and 'b' , respectively , prove that 4b2 (square)=a2 (square) +3r2(square)..

plzz help... this ques. is making me go crazy...



Follow the has been solved there..
1 5 1
exuse me ... i m sry but i need a little more help
Yeah.. How can I help you..??????
i didnt get the last two lines..
In equation (iv) multiple with 3 on both side.... Then add a^2 on both side... By these we get 4a^2 which is equal to b^2.. replace it... then u will get what u want...
Did you get the last part..??????